Re: [bolger] Re: Help for the mathematically impaired, ME
Thanks ALL,
I would like to express my appreciation to all that came foreward
with your assisstance when I needed it. Thanks, Stan
I would like to express my appreciation to all that came foreward
with your assisstance when I needed it. Thanks, Stan
On Thu, 26 Apr 2001pateson@...wrote:
Here's an important that I do not know if it was raised or not:
Measure your cylinders from the outside, not the inside. Pipe is usually
described for sale by it's inside dimension, which makes sense, but for
figuring displacement, you should measure the outer diameter.
> Late at night and got nothing to do, you got lots of advice, andI thought so too, but quit reading the responses.
> correct formulas, most of it correct.
Here's an important that I do not know if it was raised or not:
Measure your cylinders from the outside, not the inside. Pipe is usually
described for sale by it's inside dimension, which makes sense, but for
figuring displacement, you should measure the outer diameter.
Late at night and got nothing to do, you got lots of advice, and
correct formulas, most of it correct. If you did not get the answer
you were looking for, let me know via email and I will give you you
what you want to know. I just went through the same thing with my son
who was wanting to put a solar hot water pre-heater on top of his
house. Had to figure volumn of each 100' lenght of 1 1/4" black
plastic pipe. Give me the dimentions of cyllinder and I will give
you the volumn. And tell you how to do it, if you want to know.
Pat Patteson
pateson@...
correct formulas, most of it correct. If you did not get the answer
you were looking for, let me know via email and I will give you you
what you want to know. I just went through the same thing with my son
who was wanting to put a solar hot water pre-heater on top of his
house. Had to figure volumn of each 100' lenght of 1 1/4" black
plastic pipe. Give me the dimentions of cyllinder and I will give
you the volumn. And tell you how to do it, if you want to know.
Pat Patteson
pateson@...
--- In bolger@e..., Stan Muller <smuller@i...> wrote:
> Please, Help!!!!
> I have a problem, well, I've got several, but there is one that
you
> can assist with.
> How do I find the volume of a cylinder? Once I have that, how do
I
> figure the displacement of that volume.
> Does anyone know of a web site that has the formulas for things
like
> volume, area, etc.?
> Thanks for the help, Stan Snow Goose.
By the way, I forgot to ask you where you live.
Roger
I am in Tooleedoo ohio. South of Deetroit.
__________________________________________________
Do You Yahoo!?
Yahoo! Auctions - buy the things you want at great prices
http://auctions.yahoo.com/
Roger
I am in Tooleedoo ohio. South of Deetroit.
__________________________________________________
Do You Yahoo!?
Yahoo! Auctions - buy the things you want at great prices
http://auctions.yahoo.com/
Hi Roger,
YES, YES, I WILL need a test pilot!!! ;-) And don't let the people
with good sense, on the list, talk you out of it!
Stan, Diving Duck.
YES, YES, I WILL need a test pilot!!! ;-) And don't let the people
with good sense, on the list, talk you out of it!
Stan, Diving Duck.
> Can i come play!!! HUH! CAN I! CAN! I CAN I!!!!
> PUULEEEASE!!!
> Roger
You could apply a wet tank area to reach closer to
netural bouyancy.
Have you considered a Hookah for that depth, they'll
go 25 - 30 ft beyond that breathing tends to get
difficult.
At 33 feet you have 300 minutes down time without
having to decompress.
Me be diver.
Roger
--- Stan Muller <smuller@...> wrote:
Do You Yahoo!?
Yahoo! Auctions - buy the things you want at great prices
http://auctions.yahoo.com/
netural bouyancy.
Have you considered a Hookah for that depth, they'll
go 25 - 30 ft beyond that breathing tends to get
difficult.
At 33 feet you have 300 minutes down time without
having to decompress.
Me be diver.
Roger
--- Stan Muller <smuller@...> wrote:
> Bless you Porky,__________________________________________________
> I just managed to stumble through the math, and
> came up with the
> 1256. then with the addition of the conning tower
> part, I came up with a
> total displacement of 1512. To tell you the truth, I
> didn't believe my
> numbers until your post. With the hull weight, my
> weight, batteries,
> trolling motors and tanks and plumbing, I'll still
> need over a thousand
> pounds to sink the fool thing.
> The tender for the Diving Duck will be the Bolger
> Micro motor launch
> Snow Goose.
> There now I'm back on topic. ;-)
> Thanks, all for the help,
> Stan
>
Do You Yahoo!?
Yahoo! Auctions - buy the things you want at great prices
http://auctions.yahoo.com/
Can i come play!!! HUH! CAN I! CAN! I CAN I!!!!
PUULEEEASE!!!
Roger
--- Stan Muller <smuller@...> wrote:
Do You Yahoo!?
Yahoo! Auctions - buy the things you want at great prices
http://auctions.yahoo.com/
PUULEEEASE!!!
Roger
--- Stan Muller <smuller@...> wrote:
> (Why *else* would__________________________________________________
> anyone want to know the displacement of a cylinder?
> :-)
>
> To all that are assisting the math challanged;
> A friend of mine gave me two like new aluminum
> tanks. one is 24" x
> 75" for the hull, and the other is 21" x 62" to make
> the conning tower
> out of, using about two foot of it. We are trying to
> find out how much
> weight it would take to sink it. if it can be done,
> it will be a shallow
> dry submersable (about 10 foot running depth with a
> surface supplied air
> system. and a tether up so it can't sink any further
> than about 15 feet.
> Sound like fun?
> Stan, Diving Duck.
>
Do You Yahoo!?
Yahoo! Auctions - buy the things you want at great prices
http://auctions.yahoo.com/
Hi Tom,
(flame) What do you mean, bad at math!!! I would have to go to night
school to progress up to the point of being, "bad at math. ;-)
(flame) What do you mean, bad at math!!! I would have to go to night
school to progress up to the point of being, "bad at math. ;-)
All I can say is I would want to have things right with Jesus before
going for a dive in a submarine engineered by someone who was bad at
math. :-)
Tom K
going for a dive in a submarine engineered by someone who was bad at
math. :-)
Tom K
> A friend of mine gave me two like new aluminum tanks. one is 24" x
> 75" for the hull, and the other is 21" x 62" to make the conning tower
> out of, using about two foot of it. We are trying to find out how much
> weight it would take to sink it. if it can be done, it will be a shallow
> dry submersable (about 10 foot running depth with a surface supplied air
> system. and a tether up so it can't sink any further than about 15 feet.
> Sound like fun?
> Stan, Diving Duck.
>
To square a number you multipy it by itself, thus 2 square is 2x2 or 4
1 square would be 1 x 1 or 1.
Micahel Surface
Get your FREE download of MSN Explorer athttp://explorer.msn.com
1 square would be 1 x 1 or 1.
Micahel Surface
>From: Stan Muller <smuller@...>_________________________________________________________________
>Reply-To:bolger@yahoogroups.com
>To:bolger@yahoogroups.com
>Subject: Re: [bolger] Re: Help for the mathematically impaired, ME
>Date: Sat, 21 Apr 2001 19:14:42 -0500
>
>Thank you Lincoln,
>My cylinder is 2' diameter, and 6 1/4 feet high. So;
>that's 3.14 X 1 squared X 6.25
> Which leaves me asking what is 1 squared?
>I did say that I was mathematically impaired, didn't I?
>
>Thanks, Stan, SG
Get your FREE download of MSN Explorer athttp://explorer.msn.com
A cylinder is
volume = pi * radius^2 * length.
The displacement of that cylinder in freshwater is 62.5 lbs/cubic foot or
0.0362 lbs/cu inch.
Best,
JB
volume = pi * radius^2 * length.
The displacement of that cylinder in freshwater is 62.5 lbs/cubic foot or
0.0362 lbs/cu inch.
Best,
JB
----- Original Message -----
From: "Stan Muller" <smuller@...>
To: "Bolger egroups" <bolger@yahoogroups.com>
Sent: Saturday, April 21, 2001 7:31 PM
Subject: [bolger] Help for the mathematically impaired, ME
| Please, Help!!!!
| I have a problem, well, I've got several, but there is one that you
| can assist with.
| How do I find the volume of a cylinder? Once I have that, how do I
| figure the displacement of that volume.
| Does anyone know of a web site that has the formulas for things like
| volume, area, etc.?
| Thanks for the help, Stan Snow Goose.
|
| Bolger rules!!!
| - no cursing, flaming, trolling, or spamming
| - no flogging dead horses
| - add something: take "thanks!" and "ditto!" posts off-list.
| - stay on topic and punctuate
| - add your comments at the TOP and SIGN your posts
| - To order plans: Mr. Philip C. Bolger, P.O. Box 1209, Gloucester, MA,
01930, Fax: (978) 282-1349
|
|
| Your use of Yahoo! Groups is subject tohttp://docs.yahoo.com/info/terms/
|
|
Bless you Porky,
I just managed to stumble through the math, and came up with the
1256. then with the addition of the conning tower part, I came up with a
total displacement of 1512. To tell you the truth, I didn't believe my
numbers until your post. With the hull weight, my weight, batteries,
trolling motors and tanks and plumbing, I'll still need over a thousand
pounds to sink the fool thing.
The tender for the Diving Duck will be the Bolger Micro motor launch
Snow Goose.
There now I'm back on topic. ;-)
Thanks, all for the help,
Stan
I just managed to stumble through the math, and came up with the
1256. then with the addition of the conning tower part, I came up with a
total displacement of 1512. To tell you the truth, I didn't believe my
numbers until your post. With the hull weight, my weight, batteries,
trolling motors and tanks and plumbing, I'll still need over a thousand
pounds to sink the fool thing.
The tender for the Diving Duck will be the Bolger Micro motor launch
Snow Goose.
There now I'm back on topic. ;-)
Thanks, all for the help,
Stan
Stan,
Let's keep it 1' diameter by 6.25' high (if you do it in inches you
have to divide by 1728 to get the cubic feet before you calculate the
displacement, thereby making things more complicated). 1 squared is 1
(1x1=1) times 3.141 (pi) = 3.141 x 6.25' = 19.63125 cu ft x 64 (lbs in
a cubic foot of seawater) = 1256.4 lbs. displacement, if the cylinder
is fully immersed. Of course, if you wished to sail your cylinder in
mercury or grain alcohol, the displacement would different....
porky (david galvin)
Let's keep it 1' diameter by 6.25' high (if you do it in inches you
have to divide by 1728 to get the cubic feet before you calculate the
displacement, thereby making things more complicated). 1 squared is 1
(1x1=1) times 3.141 (pi) = 3.141 x 6.25' = 19.63125 cu ft x 64 (lbs in
a cubic foot of seawater) = 1256.4 lbs. displacement, if the cylinder
is fully immersed. Of course, if you wished to sail your cylinder in
mercury or grain alcohol, the displacement would different....
porky (david galvin)
--- In bolger@y..., Stan Muller <smuller@i...> wrote:
> Lets make this easy, my cylinder is 24 inches in diameter, and is 75
> inches high. What's the displacement?
> Thanks, Stan
(Why *else* would
anyone want to know the displacement of a cylinder? :-)
To all that are assisting the math challanged;
A friend of mine gave me two like new aluminum tanks. one is 24" x
75" for the hull, and the other is 21" x 62" to make the conning tower
out of, using about two foot of it. We are trying to find out how much
weight it would take to sink it. if it can be done, it will be a shallow
dry submersable (about 10 foot running depth with a surface supplied air
system. and a tether up so it can't sink any further than about 15 feet.
Sound like fun?
Stan, Diving Duck.
anyone want to know the displacement of a cylinder? :-)
To all that are assisting the math challanged;
A friend of mine gave me two like new aluminum tanks. one is 24" x
75" for the hull, and the other is 21" x 62" to make the conning tower
out of, using about two foot of it. We are trying to find out how much
weight it would take to sink it. if it can be done, it will be a shallow
dry submersable (about 10 foot running depth with a surface supplied air
system. and a tether up so it can't sink any further than about 15 feet.
Sound like fun?
Stan, Diving Duck.
Lets make this easy, my cylinder is 24 inches in diameter, and is 75
inches high. What's the displacement?
Thanks, Stan
inches high. What's the displacement?
Thanks, Stan
Thank you Lincoln,
My cylinder is 2' diameter, and 6 1/4 feet high. So;
that's 3.14 X 1 squared X 6.25
Which leaves me asking what is 1 squared?
I did say that I was mathematically impaired, didn't I?
Thanks, Stan, SG
My cylinder is 2' diameter, and 6 1/4 feet high. So;
that's 3.14 X 1 squared X 6.25
Which leaves me asking what is 1 squared?
I did say that I was mathematically impaired, didn't I?
Thanks, Stan, SG
In a message dated 04/21/2001 7:<BR32:<BR25 PM
Eastern Daylight ,smuller@...writes:
the volume of a cylinder is the area X height. Get your dimensions in the
same units, then get the area of the circle, pi x r^2, that is, take the
radius of the circle and square that, then multiply x pi (3.14159...) Now,
multiply that product timesthe height.
Say your cylinder is 6" in diameter and 5" high (or cm, or meters, etc.) the
radius is 3", squared is 9, that times pi gives the area of the circle
(bore???) or 28.27 appx. Now multiply that times the height (stroke???) or
5". 5 X 28.27 = 141.35 cubic inches. Now, if you are figuring displacement of
an engine, multiply that times the number of cylinders. (Why *else* would
anyone want to know the displacement of a cylinder? :-)
BTW, displacement (volume) is equal to the volume you calculated...no
difference.
Cheers/Carron
Eastern Daylight ,smuller@...writes:
> How do I find the volume of a cylinder? Once I have that, how do IStan,
> figure the displacement of that volume.
the volume of a cylinder is the area X height. Get your dimensions in the
same units, then get the area of the circle, pi x r^2, that is, take the
radius of the circle and square that, then multiply x pi (3.14159...) Now,
multiply that product timesthe height.
Say your cylinder is 6" in diameter and 5" high (or cm, or meters, etc.) the
radius is 3", squared is 9, that times pi gives the area of the circle
(bore???) or 28.27 appx. Now multiply that times the height (stroke???) or
5". 5 X 28.27 = 141.35 cubic inches. Now, if you are figuring displacement of
an engine, multiply that times the number of cylinders. (Why *else* would
anyone want to know the displacement of a cylinder? :-)
BTW, displacement (volume) is equal to the volume you calculated...no
difference.
Cheers/Carron
> How do I find the volume of a cylinder?The volume of a cylinder is the area of the end times the length. The
area of the end (or base) is PI*R^2, (pie are squared), or 3.11416 *
the radius squared.
The displacement in sea water is 64 lb/ft^3
(sixty four pounds per cubic foot). That is with the cylinder
completly submerged.
So, if the cylinder is 1 foot long, and one foot in diameter (i.e.
the radius is 0.5 ft) the the displacement is
64lb/ft^3 * one ft long * 3.14159 * 0.5 * 0.5
Peter
Don't know re web site. Many other places to look. Formula is 3.14 X (radius squared) X height
displacement is about 64 lbs per cubic foot in salt water, or is that 62? About that, anyway.
use feet in all your calculations
displacement is about 64 lbs per cubic foot in salt water, or is that 62? About that, anyway.
use feet in all your calculations
--- In bolger@y..., Stan Muller <smuller@i...> wrote:
> Please, Help!!!!
> I have a problem, well, I've got several, but there is one that you
> can assist with.
> How do I find the volume of a cylinder? Once I have that, how do I
> figure the displacement of that volume.
> Does anyone know of a web site that has the formulas for things like
> volume, area, etc.?
> Thanks for the help, Stan Snow Goose.
Please, Help!!!!
I have a problem, well, I've got several, but there is one that you
can assist with.
How do I find the volume of a cylinder? Once I have that, how do I
figure the displacement of that volume.
Does anyone know of a web site that has the formulas for things like
volume, area, etc.?
Thanks for the help, Stan Snow Goose.
I have a problem, well, I've got several, but there is one that you
can assist with.
How do I find the volume of a cylinder? Once I have that, how do I
figure the displacement of that volume.
Does anyone know of a web site that has the formulas for things like
volume, area, etc.?
Thanks for the help, Stan Snow Goose.