Re: More help for the mathematically challenged
Thanks. I did it the triangles way and (using 7'6" for the dimension
tack-to-peak) got about 33.6 sq. feet -- that should do it.
Garth
calculate the area that way. Don't worry about scaling errors; a
couple of percent won't make any difference in how the boat sails.
the leach?
tack-to-peak) got about 33.6 sq. feet -- that should do it.
Garth
> Anyway, to do it graphically, divide the figure up into triangles,or rectangles and triangles (right triangles are easier) and
calculate the area that way. Don't worry about scaling errors; a
couple of percent won't make any difference in how the boat sails.
> > So, how do you calculate the area of sail (a little standinglug) 4'3" on the luff, 5'3" on the head, 6'3" on the foot, and 7' on
the leach?
You can't do it from the information you gave. You could with the
equivalent dimensions for a triangular sail, but not a four-sided
one. There are lots of different-shaped and sized sails that could
be made with those dimensions (Imagine four sticks of those lengths,
tacked together with pins at the corners - you can change the shape
of the figure, which you can't do with a triangle). The additional
piece of information needed is the angle of any one of the corners.
Anyway, to do it graphically, divide the figure up into triangles, or
rectangles and triangles (right triangles are easier) and calculate
the area that way. Don't worry about scaling errors; a couple of
percent won't make any difference in how the boat sails.
Keith Wilson
equivalent dimensions for a triangular sail, but not a four-sided
one. There are lots of different-shaped and sized sails that could
be made with those dimensions (Imagine four sticks of those lengths,
tacked together with pins at the corners - you can change the shape
of the figure, which you can't do with a triangle). The additional
piece of information needed is the angle of any one of the corners.
Anyway, to do it graphically, divide the figure up into triangles, or
rectangles and triangles (right triangles are easier) and calculate
the area that way. Don't worry about scaling errors; a couple of
percent won't make any difference in how the boat sails.
Keith Wilson
--- In bolger@y..., garth@b... wrote:
> So, how do you calculate the area of sail (a little standing lug)
> 4'3" on the luff, 5'3" on the head, 6'3" on the foot, and 7' on the
> leach?
garth@... wrote:
So, how do you calculate the area of sail (a little standing lug)
4'3" on the luff, 5'3" on the head, 6'3" on the foot, and 7' on the
leach?
I'm sketching out a rig for my sailing pirogue. It should be smaller
than the 40 sq. ft. sail recommended for the Bolger Pirogue -- as the
Michalak Piragua has a narrower beam.
Garth
(and who's buried in Grant's Tomb, anyway?)
Jim
OK -- this is a bit embarassing, as I KNOW I once knew all this stuff
-- back in junior high school. There was even a brief time when I
could do integral calculus. Yeesh. All that useful knowledge pushed
aside to make room for "Simpsons" trivia . . .
So, how do you calculate the area of sail (a little standing lug)
4'3" on the luff, 5'3" on the head, 6'3" on the foot, and 7' on the
leach?
I'm sketching out a rig for my sailing pirogue. It should be smaller
than the 40 sq. ft. sail recommended for the Bolger Pirogue -- as the
Michalak Piragua has a narrower beam.
Garth
(and who's buried in Grant's Tomb, anyway?)
-- back in junior high school. There was even a brief time when I
could do integral calculus. Yeesh. All that useful knowledge pushed
aside to make room for "Simpsons" trivia . . .
So, how do you calculate the area of sail (a little standing lug)
4'3" on the luff, 5'3" on the head, 6'3" on the foot, and 7' on the
leach?
I'm sketching out a rig for my sailing pirogue. It should be smaller
than the 40 sq. ft. sail recommended for the Bolger Pirogue -- as the
Michalak Piragua has a narrower beam.
Garth
(and who's buried in Grant's Tomb, anyway?)